special BA?
silahkan..
Nomor 3a
[tex] \frac{ {2}^{2}. {2}^{3} . {2}^{4}. {2}^{5}}{ {2}^{7}. {2}^{6}} \\ \\ = \frac{ {2}^{2 + 3 + 4 + 5} }{ {2}^{7 + 6} } \\ \\ = \frac{ {2}^{14} }{ {2}^{13} } \\ \\ = {2}^{14 - 13} \\ \\ = {2}^{1} \\ \\ = 2[/tex]
[tex] \\ [/tex]
Nomor 3b
[tex] \frac{ {2}^{2} . {2}^{3} . {2}^{4}. {2}^{5} }{ {6}^{2} . {20}^{2} } \\ \\ = \frac{ {2}^{2 + 3 + 4 + 5} }{(2 \times 3) {}^{2}. {(5 \times {2}^{2} )}^{2} } \\ \\ = \frac{ {2}^{14} }{ {2}^{2}. {3}^{2}. {5}^{2}. {2}^{4} } \\ \\ = \frac{ {2}^{14} }{ {2}^{2 + 4} . {3}^{2} . {5}^{2} } \\ \\ = \frac{ {2}^{14} }{ {2}^{6}.9.25 } \\ \\ = \frac{ {2}^{14 - 2} }{225} \\ \\ = \frac{ {2}^{12} }{225} \\ \\ = \frac{4096}{225} \\ \\ =18,2[/tex]
[tex] \\ [/tex]
Nomor 3c
[tex] \frac{ {6}^{3}. {8}^{4}. {9}^{2} }{ {3}^{5}. {4}^{4}. {2}^{2} } \\ \\ = \frac{ {(2 \times 3)}^{3}. { ({2}^{3} )}^{4}. { ({3}^{2} )}^{2} }{ {3}^{5} . {( {2}^{2}) }^{4}. {2}^{2} } \\ \\ = \frac{ {2}^{3}. {3}^{3}. {2}^{12}. {3}^{4} }{ {3}^{5}. {2}^{8}. {2}^{2} } \\ \\ = {2}^{(3 + 12 )- (8 + 2)} \times {3}^{(3 + 4) - 5} \\ \\ = {2}^{15 - 10} \times {3}^{7 - 5} \\ \\ = {2}^{5} \times {3}^{2} \\ \\ = 32 \times 9 \\ \\ = 288[/tex]
mohon koreksinya yaa, hehee
semoga betul^
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